How to Learn from the Best!
Watercolour artists often provide an eclectic mix of subjects for public viewing and it is always worth attending any new exhibitions that may be advertised as you can learn a great deal from other artists and this will only serve to help you in your own paintings. Some exhibitions will include work from a variety of watercolour artists and many of those artists will be attending to talk to the public about their paintings and their inspiration. If you have a desire to become one of many renowned watercolour artists in your own right, then it is worth going along to a new exhibition and taking the opportunity to ask some key questions.
Whether the watercolour artists are personal favourites or even if you have never had the chance to see any of their paintings before, it is an ideal opportunity to ask the type of questions that will help you with your own paintings such as:
- When did they first begin to use watercolours?
- Have they always painted in this genre?
- What did they find most difficult to learn when learning how to use watercolours?
- How did you start to sell their work?
- What was the point when they decided they wanted to become professional watercolour artists?
When you are asking questions, make sure that you do not turn it into some form of interrogation, most watercolour artists will be happy to discuss painting, technical issues and to give you an insight into their life as professional artists whilst at an exhibition, however it is important that you build rapport with the artist and show a genuine interest in their work.
If there are any other questions about particular aspects of painting in this medium or indeed, you would like personal tuition, it is a good time to ask the artist. Bear in mind that not all artists are good teachers but if you admire their work and feel an affinity with their collection, then they may be the right person to guide you. Just bear in mind that to join the professional watercolour artists? rank, a great deal of practice and learning will be involved.